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Is that supposed to be 16x^7 at the end ?
is sqrt[3] supposed to mean "cube root" ?
What is supposed to happen here ?
Are we simplifying ?
-3x\sqrt[3]{54x^4} + 2\sqrt[3]{16x7}
2 answers
If I read your notation right, you have
-3x/√3 54x^4 + 2/√3 16x^7
Seems kind of odd, so maybe it's wrong.
But whatever, is there a question in here somewhere?
Ahh. Maybe you have
-3x∛(54x^4) + 2∛(16x^7)
note that
∛27x^3 = 3x
∛8x^6 = 2x^2
Maybe that will get you started.
-3x/√3 54x^4 + 2/√3 16x^7
Seems kind of odd, so maybe it's wrong.
But whatever, is there a question in here somewhere?
Ahh. Maybe you have
-3x∛(54x^4) + 2∛(16x^7)
note that
∛27x^3 = 3x
∛8x^6 = 2x^2
Maybe that will get you started.
1 answer