When x=-1, substituting into the equation gives:
3(-1) - 5y = 19
-3 - 5y = 19
-5y = 22
y = -22/5
When x=0, substituting into the equation gives:
3(0) - 5y = 19
-5y = 19
y = -19/5
When x=1, substituting into the equation gives:
3(1) - 5y = 19
3 - 5y = 19
-5y = 16
y = -16/5
3X - 5Y = 19
Then find the value of y for each value of x. (Type an integer or as a simplified fraction) (3 points)
When x=−1 , the value of y is
When x=0 , the value of y is
When x=1 , the value of y is
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