(3x^3y)^4 - (7x^5y)^2 times x^2y^2

Answer 1

To simplify the expression, first expand the terms of the exponents:

(3x^3y)^4 = 3^4 * x^(3*4) * y^4 = 81x^12y^4
(7x^5y)^2 = 7^2 * x^(5*2) * y^2 = 49x^10y^2

Now substitute these values back into the expression:

(81x^12y^4) - (49x^10y^2) times x^2y^2
= 81x^12y^4 - 49x^10y^2 times x^2y^2

Now distribute the x^2y^2 to each term:

= 81x^14y^6 - 49x^12y^4

Therefore, the simplified expression is 81x^14y^6 - 49x^12y^4.