(3x^3-x^2+2x-4)dx

--------------------------
sqrt x^2-3x+2

2 answers

the answer is supposed to be between 60000 and 70000
Is this supposed to be some integral?
If you want a constant answer you need a lower and upper value.
I gave the algebraic expression to Wolfram, don't know if this helps.
(I certainly would not know how to integrate this right now)

http://www.wolframalpha.com/input/?i=integral+(3x%5E3-x%5E2%2B2x-4)%2F%E2%88%9A(x%5E2-3x%2B2)dx
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