3x-2y=8
2x=2y=22
How i solve with substitution?
6 answers
Please correct your typo.
how do i solve with substitution?
3x-2y=8
2x=2y=22
===========
I assume you mean
3x-2y=8
2x-2y=22 ?????
if so then get y = some function of x from the second equation
2 x - 2 y = 22
is
x - y = 11
or
y = (x - 11)
substitute that in the first equation
3 x - 2 (x - 11) = 8
3 x - 2 x + 22 = 8
x = - 14
then go back for y
y - -14 - 11 = -25
2x=2y=22
===========
I assume you mean
3x-2y=8
2x-2y=22 ?????
if so then get y = some function of x from the second equation
2 x - 2 y = 22
is
x - y = 11
or
y = (x - 11)
substitute that in the first equation
3 x - 2 (x - 11) = 8
3 x - 2 x + 22 = 8
x = - 14
then go back for y
y - -14 - 11 = -25
If I guessed wrong on your typo, then I told you how to do it anyway.
Since the + and = signs are on the same key, I suspect you meant
3x-2y = 8
2x+2y = 22 ---->x+y=11 --->y = 11-x
sub into the 1st
3x - 2(11-x) = 8
3x - 22+2x = 8
5x = 30
x = 6
then y = 11-6 = 5
3x-2y = 8
2x+2y = 22 ---->x+y=11 --->y = 11-x
sub into the 1st
3x - 2(11-x) = 8
3x - 22+2x = 8
5x = 30
x = 6
then y = 11-6 = 5
Good mind reading :)
1 answer