3x+2y=15

Y=6x
Solve by substitution

1 answer

To solve the system of equations using substitution, we start with the two equations:

  1. \( 3x + 2y = 15 \)
  2. \( y = 6x \)

We can substitute the expression for \( y \) from the second equation into the first equation.

Substituting \( y = 6x \) into \( 3x + 2y = 15 \):

\[ 3x + 2(6x) = 15 \]

Now simplify the equation:

\[ 3x + 12x = 15 \] \[ 15x = 15 \]

Next, divide both sides by 15 to solve for \( x \):

\[ x = 1 \]

Now that we have \( x \), we can substitute it back into the equation \( y = 6x \) to find \( y \):

\[ y = 6(1) = 6 \]

Thus, the solution to the system of equations is:

\[ (x, y) = (1, 6) \]

So the final answer is:

\[ \boxed{(1, 6)} \]

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