(3x^2+2x-3)-(x^2-2x+1)
would the answer be 2x^2+4x+4
or did I do something wrong
2 answers
No, it would be 2x^2+4x-4
(3x^2+2x-3)-(x^2-2x+1) =
3x^2 + 2x -3 - x^2 +2x -1 =
3x^2 - x^2 + 2x + 2x -3 -1 =
2x^2 + 4x - 4
3x^2 + 2x -3 - x^2 +2x -1 =
3x^2 - x^2 + 2x + 2x -3 -1 =
2x^2 + 4x - 4