To solve this system of equations, we can use the method of substitution or elimination.
Let's use the method of substitution:
From the first equation, we can solve for x:
3x = 2 - 19y
x = (2 - 19y)/3
Now, substitute the value of x in the second equation:
19(2 - 19y)/3 + 3y = 130
Simplify the equation:
38 - 361y/3 + 3y = 130
Multiply through by 3 to get rid of the fraction:
114 - 361y + 9y = 390
Combine like terms:
-352y = 276
Divide by -352 to solve for y:
y = -276/-352
y = 69/88
Substitute this value back into the first equation to solve for x:
3x + 19(69/88) = 2
3x + 1311/88 = 2
3x = 1768/88 - 1311/88
3x = 457/88
x = 457/264
Therefore, the solution to the system of equations is x = 457/264 and y = 69/88.
3x + 19y = 2 19x + 3y = 130 What is the solution for the system of equations above?
1 answer