note from #2 that
x = 21y/(2y+1)
put that into #1 and you have
3*21y/(2y+1) + 14y = 5y*21y/(2y+1)
63y + 14y(2y+1) = 105y^2
77y^2-77y = 0
77y(y-1) = 0
Now you have two solutions for y. Use them to get associated solutions for x.
3x + 14y = 5xy
21y - x = 2xy
kindly solve the pair of linear equation
4 answers
I don't now
Not got it 🤔😒
1.Divide the two equations by xy
2.You will now have two equations.
3.Solve it by multiplying and cancelling , and find x and y by substituting.
2.You will now have two equations.
3.Solve it by multiplying and cancelling , and find x and y by substituting.
1 answer