3log2 +log20 -log1.6

Answer 1

Using logarithm rules, we can simplify this expression as follows:

3log2 + log20 - log1.6

= log(2^3) + log(20) - log(1.6) (logarithm rule: log(a) + log(b) = log(ab))

= log(8) + log(20) - log(1.6) (2^3 = 8)

Now, let's use another logarithm rule: log(a) - log(b) = log(a/b)

= log(8 * 20 / 1.6) (logarithm rule: log(a) + log(b) = log(ab))

= log(160)

Therefore, the simplified expression is log(160).