(3b−2c)−(6c+2b)−(b+c)

Answer 1

To simplify the expression (3b−2c)−(6c+2b)−(b+c), we can start by removing the parentheses.

First, we distribute the negative sign to the terms inside the first parentheses:
(3b−2c)−(6c+2b)−(b+c) = 3b - 2c - 6c - 2b - (b + c)

Next, we distribute the negative sign to the terms inside the second parentheses:
3b - 2c - 6c - 2b - (b + c) = 3b - 2c - 6c - 2b - b - c

Now, we can combine like terms. Let's group the b terms and the c terms:
(3b - 2b - 2b - b) + (-2c - 6c - c) = -2b - 9c

Therefore, the simplified expression is -2b - 9c.