(3b-2)/(b+1) = (4)- (b+2)/(b-1)

Question

The (b+2)/(b-1) is separate from the 4. the 4 isn't included in the division

Answer 1

multipy both sides by (b+1)(b-1)

(3b-2)(b-1)= 4(b^2-1) - (b+2)(b+1)

now foil each term out, then combine terms, and factor (or use the quadratic equation).

Answer 2

does b=2???