Yes, that looks correct.
Continue by substituting in a=-10 into one of the equations to find b.
3a-2b=12
2a+b=1
multiply eq 2 x 2
4a+2b=2
eliminate b by subtracting eq (1) from (3)
4a+2b=2
3a-2b=12
a=-10 am i going right so far??
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