Using a certain ramp at the skate park, a skater's height off the ground, in feet, is modeled by the equation y=0.25x2−4x+19

, where x is the skater's horizontal distance from the jumping platform. How far from the jumping platform is a skateboarder when they are at their minimum height off the ground?(

1 answer

To find the horizontal distance \( x \) from the jumping platform where the skater is at their minimum height, we need to determine the vertex of the parabola represented by the equation \( y = 0.25x^2 - 4x + 19 \).

For a quadratic equation of the form \( ax^2 + bx + c \), the \( x \) value of the vertex (which represents the minimum or maximum point) can be calculated using the formula:

\[ x = -\frac{b}{2a} \]

In our equation, the coefficients are:

  • \( a = 0.25 \)
  • \( b = -4 \)
  • \( c = 19 \)

Substituting the values of \( a \) and \( b \) into the vertex formula:

\[ x = -\frac{-4}{2(0.25)} = \frac{4}{0.5} = 8 \]

Thus, the skateboarder is 8 feet away from the jumping platform when they are at their minimum height off the ground.