To determine the theoretical probability of landing on G for each spinner, we will count the number of times G appears on each spinner and divide that by the total number of sections on that spinner.
Spinner 2: R,R,G,G,G,R,R,G
- Total sections: 8 (R,R,G,G,G,R,R,G)
- Number of G's: 4
The probability of landing on G for Spinner 2 is: \[ \text{Probability} = \frac{\text{Number of G's}}{\text{Total Sections}} = \frac{4}{8} = \frac{1}{2} = 0.5 \text{ or } 50% \]
Spinner 3: O,O,O,O,Y,Y,Y,Y
- Total sections: 8 (O,O,O,O,Y,Y,Y,Y)
- Number of G's: 0
The probability of landing on G for Spinner 3 is: \[ \text{Probability} = \frac{0}{8} = 0 \text{ or } 0% \]
Summary:
- Spinner 2: Probability of landing on G = 0.5 or 50%
- Spinner 3: Probability of landing on G = 0 or 0%
From the options listed:
- The probability for Spinner 2 (50%) aligns with the theoretical probability we calculated.
- The probability for Spinner 3 (0) is not listed but is valid.
For the purpose of your original question, only Spinner 2 yields a probability from the listed options. The answer for Spinner 2 is:
- 50% (or as a fraction, \(\frac{1}{2}\))