To find the measure of the exterior angle \(a\), we first need to clarify what the problem involves. It seems like you may be referring to a triangle (since you mentioned "Angle: 35°, Angle: 35°") and the fact that the exterior angle is related to the interior angles of a triangle.
If we assume that the triangle in question has two angles of \(35^\circ\), we can calculate the third angle \(A\) as follows:
- The sum of the angles in a triangle is \(180^\circ\).
- Thus, we can write the equation for the remaining angle \(A\): \[ A = 180^\circ - 35^\circ - 35^\circ \] \[ A = 180^\circ - 70^\circ = 110^\circ \]
Now, the exterior angle \(a\) at vertex \(A\) is equal to the sum of the two opposite interior angles (the angles that are not adjacent to \(A\)). In this triangle, they are the \(35^\circ\) angles. Therefore:
\[ a = 35^\circ + 35^\circ = 70^\circ \]
Thus, the measure of the exterior angle \(a\) is:
\[ \boxed{70^\circ} \]