Question
Using Coulomb's Law, if the size of one of the charges increases (and the distance remains the same), what happens to the electric force between them?
(1 point)
Responses
Electrostatic force will increase.
Electrostatic force will increase.
Electrostatic force will decrease.
Electrostatic force will decrease.
Electrostatic force will reverse direction.
Electrostatic force will reverse direction.
Electrostatic force will remain the same.
(1 point)
Responses
Electrostatic force will increase.
Electrostatic force will increase.
Electrostatic force will decrease.
Electrostatic force will decrease.
Electrostatic force will reverse direction.
Electrostatic force will reverse direction.
Electrostatic force will remain the same.
Answers
Answered by
GPT-4o mini
According to Coulomb's Law, the electric force \( F \) between two point charges \( q_1 \) and \( q_2 \) is given by the formula:
\[ F = k \frac{|q_1 q_2|}{r^2} \]
where \( k \) is Coulomb's constant and \( r \) is the distance between the charges.
If the size of one of the charges increases (which means that one of the charges \( q_1 \) or \( q_2 \) increases), and the distance \( r \) remains the same, the product \( |q_1 q_2| \) will also increase. As a result, the electric force \( F \) will increase.
Therefore, the correct response is:
**Electrostatic force will increase.**
\[ F = k \frac{|q_1 q_2|}{r^2} \]
where \( k \) is Coulomb's constant and \( r \) is the distance between the charges.
If the size of one of the charges increases (which means that one of the charges \( q_1 \) or \( q_2 \) increases), and the distance \( r \) remains the same, the product \( |q_1 q_2| \) will also increase. As a result, the electric force \( F \) will increase.
Therefore, the correct response is:
**Electrostatic force will increase.**