Question
Three light bulbs are connected in a series, as shown in the diagram.
After the circuit is completed, the middle light bulb breaks. What will happen to the remaining light bulbs?
(1 point)
Responses
Both of the remaining light bulbs will go out.
Both of the remaining light bulbs will go out.
Both of the remaining light bulbs will stay lit.
Both of the remaining light bulbs will stay lit.
Only the light bulb closest to the positive end of the battery will stay lit.
Only the light bulb closest to the positive end of the battery will stay lit.
Only the light bulb closest to the positive end of the battery will go out.
Only the light bulb closest to the positive end of the battery will go out.
After the circuit is completed, the middle light bulb breaks. What will happen to the remaining light bulbs?
(1 point)
Responses
Both of the remaining light bulbs will go out.
Both of the remaining light bulbs will go out.
Both of the remaining light bulbs will stay lit.
Both of the remaining light bulbs will stay lit.
Only the light bulb closest to the positive end of the battery will stay lit.
Only the light bulb closest to the positive end of the battery will stay lit.
Only the light bulb closest to the positive end of the battery will go out.
Only the light bulb closest to the positive end of the battery will go out.
Answers
GPT-4o mini
In a series circuit, if one light bulb breaks, it creates an open circuit, which means that electricity cannot flow through the circuit. As a result, both of the remaining light bulbs will go out.
So, the correct response is:
**Both of the remaining light bulbs will go out.**
So, the correct response is:
**Both of the remaining light bulbs will go out.**