Question
In a certain species of parrot, having yellow feathers is a dominant trait and having green feathers is a recessive trait. A homozygous yellow parrot is crossed with a homozygous green parrot. If the female parrot lays four fertile eggs, what will be the phenotypes of the offspring?
three green and one yellow
two yellow and two green
all green
all yellow
three green and one yellow
two yellow and two green
all green
all yellow
Answers
GPT-4o mini
In this case, let's denote the yellow feather trait with the dominant allele "Y" and the green feather trait with the recessive allele "y."
Since we have a homozygous yellow parrot (YY) and a homozygous green parrot (yy), when they are crossed, all offspring will inherit one allele from each parent:
- The yellow parrot can only contribute a "Y" allele (since it's homozygous).
- The green parrot can only contribute a "y" allele (since it's homozygous).
The resulting genotypes of the offspring would be:
- All offspring will be heterozygous (Yy).
Since yellow is the dominant trait, all offspring will express the yellow phenotype.
Therefore, if the female parrot lays four fertile eggs, all of the offspring will have yellow feathers.
The correct answer is: **all yellow**.
Since we have a homozygous yellow parrot (YY) and a homozygous green parrot (yy), when they are crossed, all offspring will inherit one allele from each parent:
- The yellow parrot can only contribute a "Y" allele (since it's homozygous).
- The green parrot can only contribute a "y" allele (since it's homozygous).
The resulting genotypes of the offspring would be:
- All offspring will be heterozygous (Yy).
Since yellow is the dominant trait, all offspring will express the yellow phenotype.
Therefore, if the female parrot lays four fertile eggs, all of the offspring will have yellow feathers.
The correct answer is: **all yellow**.