To find the probabilities \( P(A) \) and \( P(B) \), we can use the values from the table provided.
- \( P(A) \) represents the probability of a late arrival. The total number of late arrivals is 150, and the total number of arrivals (both on time and late) is 450. Thus,
\[ P(A) = \frac{150}{450} \]
- \( P(B) \) represents the probability of transportation by car. The total number of arrivals by car is 250, and the total number of arrivals is 450. Therefore,
\[ P(B) = \frac{250}{450} \]
To calculate \( P(A) \cdot P(B) \), we multiply these two probabilities together:
\[ P(A) \cdot P(B) = \left(\frac{150}{450}\right) \cdot \left(\frac{250}{450}\right) \]
Thus, the correct response for \( P(A) \cdot P(B) \) is:
\[ \frac{150}{450} \cdot \frac{250}{450} \]
This aligns with the first response option:
\[ 150450 \cdot 250450 \text{ (Start Fraction 150 over 450 End Fraction times Start Fraction 250 over 450 End Fraction)} \]
So the correct answer is:
150450⋅250450