Question
If a circle has a diameter of 94 kilometers and a central angle of 3π2
, then what is the length of the arc created by the angle?(1 point)
Responses
π18
Start Fraction pi over 18 End Fraction
9π
9 pi
18π
18 pi
141π2
, then what is the length of the arc created by the angle?(1 point)
Responses
π18
Start Fraction pi over 18 End Fraction
9π
9 pi
18π
18 pi
141π2
Answers
GPT-4o mini
To find the length of the arc created by a central angle in a circle, you can use the formula:
\[
\text{Arc Length} = r \cdot \theta
\]
where \( r \) is the radius of the circle and \( \theta \) is the central angle in radians.
1. **Find the radius:** The diameter is given as 94 kilometers, so the radius \( r \) is:
\[
r = \frac{diameter}{2} = \frac{94}{2} = 47 \text{ kilometers}
\]
2. **Use the central angle:** The central angle is \( \frac{3\pi}{2} \) radians.
3. **Calculate the arc length:**
\[
\text{Arc Length} = r \cdot \theta = 47 \cdot \frac{3\pi}{2}
\]
4. **Perform the multiplication:**
\[
\text{Arc Length} = 47 \cdot \frac{3\pi}{2} = \frac{141\pi}{2}
\]
So, the length of the arc created by the angle is:
\[
\frac{141\pi}{2}
\]
Among the provided options, the correct answer looks like:
\[
\frac{141\pi}{2}
\]
Therefore, the correct response is:
\(\mathbf{141\pi/2}\)
\[
\text{Arc Length} = r \cdot \theta
\]
where \( r \) is the radius of the circle and \( \theta \) is the central angle in radians.
1. **Find the radius:** The diameter is given as 94 kilometers, so the radius \( r \) is:
\[
r = \frac{diameter}{2} = \frac{94}{2} = 47 \text{ kilometers}
\]
2. **Use the central angle:** The central angle is \( \frac{3\pi}{2} \) radians.
3. **Calculate the arc length:**
\[
\text{Arc Length} = r \cdot \theta = 47 \cdot \frac{3\pi}{2}
\]
4. **Perform the multiplication:**
\[
\text{Arc Length} = 47 \cdot \frac{3\pi}{2} = \frac{141\pi}{2}
\]
So, the length of the arc created by the angle is:
\[
\frac{141\pi}{2}
\]
Among the provided options, the correct answer looks like:
\[
\frac{141\pi}{2}
\]
Therefore, the correct response is:
\(\mathbf{141\pi/2}\)