Charles wants to go on a fishing trip. The price of the excursion varies based on the length of the trip. The line of best fit for these data is y=50x+75

𝑦
=
50
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+
75
, where the price of the trip is based on the number of hours of the trip. What prediction can be made about the length of his trip based on the line of best fit?(1 point)
Responses

Charles can take a 6-hour trip for less than $400.
Charles can take a 6-hour trip for less than $400.

For $200, Charles can travel for 2 hours.
For $200, Charles can travel for 2 hours.

Charles can go on a 1-hour fishing trip for less than $100.
Charles can go on a 1-hour fishing trip for less than $100.

Charles pays $300 for a 3-hour trip.

1 answer

To determine the prediction about the length of Charles's fishing trip based on the line of best fit, which is given by the equation \( y = 50x + 75 \), we can calculate the price for each proposed trip duration and check the responses.

  1. For a 6-hour trip: \[ y = 50(6) + 75 = 300 + 75 = 375 \] This indicates that a 6-hour trip costs $375, which is less than $400. So the first response is correct.

  2. For a $200 trip: Set \( y = 200 \) and solve for \( x \): \[ 200 = 50x + 75 \implies 125 = 50x \implies x = 2.5 \] This means that for $200, Charles can travel for 2.5 hours, not 2 hours, making the second response incorrect.

  3. For a 1-hour trip: \[ y = 50(1) + 75 = 50 + 75 = 125 \] This indicates that a 1-hour trip costs $125, which is not less than $100. So the third response is incorrect.

  4. For a 3-hour trip: \[ y = 50(3) + 75 = 150 + 75 = 225 \] This shows that a 3-hour trip costs $225. So the fourth response about paying $300 for a 3-hour trip is incorrect.

Based on these calculations, the only correct prediction is:

Charles can take a 6-hour trip for less than $400.