Question
Consider a dice being thrown. Find the following probability.
P(rolling a 3 OR an even number)
Question 1 options:
0.25
0.84
0.67
0.33
P(rolling a 3 OR an even number)
Question 1 options:
0.25
0.84
0.67
0.33
Answers
GPT-4o mini
To find the probability of rolling a 3 or an even number on a standard six-sided die, we first identify the relevant outcomes.
The possible outcomes when throwing a die are:
1, 2, 3, 4, 5, 6.
Now, we determine the favorable outcomes for the event "rolling a 3 or an even number."
1. The event of rolling a 3 has 1 favorable outcome: {3}.
2. The event of rolling an even number includes: {2, 4, 6} which has 3 favorable outcomes.
Now, let's combine these events. The event of rolling a 3 and rolling an even number is mutually exclusive. Therefore, we can simply add the number of favorable outcomes:
- Favorable outcomes for rolling a 3: 1
- Favorable outcomes for rolling an even number: 3
- Total favorable outcomes: 1 + 3 = 4
Now, the total number of possible outcomes when rolling a die is 6.
Thus, the probability \( P \) of rolling a 3 or an even number is given by the formula:
\[
P(\text{rolling a 3 or an even number}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{4}{6} = \frac{2}{3} \approx 0.67
\]
So, the answer is:
**0.67**
The possible outcomes when throwing a die are:
1, 2, 3, 4, 5, 6.
Now, we determine the favorable outcomes for the event "rolling a 3 or an even number."
1. The event of rolling a 3 has 1 favorable outcome: {3}.
2. The event of rolling an even number includes: {2, 4, 6} which has 3 favorable outcomes.
Now, let's combine these events. The event of rolling a 3 and rolling an even number is mutually exclusive. Therefore, we can simply add the number of favorable outcomes:
- Favorable outcomes for rolling a 3: 1
- Favorable outcomes for rolling an even number: 3
- Total favorable outcomes: 1 + 3 = 4
Now, the total number of possible outcomes when rolling a die is 6.
Thus, the probability \( P \) of rolling a 3 or an even number is given by the formula:
\[
P(\text{rolling a 3 or an even number}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{4}{6} = \frac{2}{3} \approx 0.67
\]
So, the answer is:
**0.67**