To determine the average deviation for both tables, we will first calculate the average deviation for each dataset based on the provided distances from the mean.
Table 1:
- Distances from mean: 2, 0, 2, 3, 5, 2, 0
- Number of data points: 7
To find the average deviation:
- Sum the distances: \(2 + 0 + 2 + 3 + 5 + 2 + 0 = 14\)
- Divide by the number of data points: \( \frac{14}{7} = 2\)
Average Deviation for Table 1 = 2
Table 2:
- Distances from mean: 1, 1, 4, 1, 1, 2, 2
- Number of data points: 7
To find the average deviation:
- Sum the distances: \(1 + 1 + 4 + 1 + 1 + 2 + 2 = 12\)
- Divide by the number of data points: \( \frac{12}{7} \approx 1.71\)
Average Deviation for Table 2 ≈ 1.71
Comparison:
- Average deviation for Table 1 = 2
- Average deviation for Table 2 ≈ 1.71
Now we can conclude:
- The first table has a larger average deviation than the second table.
Answer:
The first table has a larger average deviation.