Question
A standard number cube (die) is rolled, then a coin is flipped.
What is the probability that a person rolls a 3 and then flips heads on the coin?
Question 3 options:
1/18
1/6
1/12
1/9
What is the probability that a person rolls a 3 and then flips heads on the coin?
Question 3 options:
1/18
1/6
1/12
1/9
Answers
GPT-4o mini
To find the probability of rolling a 3 on a standard number cube (die) and then flipping heads on a coin, we need to calculate the probabilities of each independent event and then multiply them.
1. **Probability of rolling a 3 on a die**:
A standard die has 6 faces. The probability of rolling a 3 is:
\[
P(\text{rolling a 3}) = \frac{1}{6}
\]
2. **Probability of flipping heads on a coin**:
A standard coin has 2 sides: heads and tails. The probability of flipping heads is:
\[
P(\text{flipping heads}) = \frac{1}{2}
\]
3. **Combined probability**:
Since these two events are independent, we can multiply their probabilities:
\[
P(\text{rolling a 3 and flipping heads}) = P(\text{rolling a 3}) \times P(\text{flipping heads}) = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}
\]
Thus, the probability that a person rolls a 3 and then flips heads on the coin is \(\frac{1}{12}\).
The correct answer is:
**1/12**
1. **Probability of rolling a 3 on a die**:
A standard die has 6 faces. The probability of rolling a 3 is:
\[
P(\text{rolling a 3}) = \frac{1}{6}
\]
2. **Probability of flipping heads on a coin**:
A standard coin has 2 sides: heads and tails. The probability of flipping heads is:
\[
P(\text{flipping heads}) = \frac{1}{2}
\]
3. **Combined probability**:
Since these two events are independent, we can multiply their probabilities:
\[
P(\text{rolling a 3 and flipping heads}) = P(\text{rolling a 3}) \times P(\text{flipping heads}) = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}
\]
Thus, the probability that a person rolls a 3 and then flips heads on the coin is \(\frac{1}{12}\).
The correct answer is:
**1/12**