To find at what point the graph of the equation \( y = (x - 32)^2 + 54 \) crosses the y-axis, we need to evaluate the equation at \( x = 0 \), since the y-axis corresponds to \( x = 0 \).
Substituting \( x = 0 \) into the equation:
\[ y = (0 - 32)^2 + 54 \] \[ y = (-32)^2 + 54 \] \[ y = 1024 + 54 \] \[ y = 1078 \]
Therefore, the graph crosses the y-axis at the point \((0, 1078)\).
So, \( y = 1078 \).