To find \((f + g)(2)\), we first need to compute \(f(2)\) and \(g(2)\), and then add those results together.
Given:
- \(f(x) = x - 1\)
- \(g(x) = x^2 + 3x - 6\)
-
Calculate \(f(2)\): \[ f(2) = 2 - 1 = 1 \]
-
Calculate \(g(2)\): \[ g(2) = (2)^2 + 3(2) - 6 \] \[ g(2) = 4 + 6 - 6 = 4 \]
-
Now, add \(f(2)\) and \(g(2)\): \[ (f + g)(2) = f(2) + g(2) = 1 + 4 = 5 \]
So, \((f + g)(2) = 5\).