A quality controller inspected 1,000 units of a product n rejected 150 units due 2 dects. Approimate da empirical robality day a until will pass da inspection

A ) 0.15%

B ) 3/20

C ) 17/20

D ) 1.5%

1 answer

To determine the empirical probability that a unit will pass inspection, we can calculate the proportion of units that were not rejected.

  1. Total units inspected: 1,000
  2. Units rejected: 150
  3. Units that passed inspection: \( 1,000 - 150 = 850 \)

Now, we can calculate the empirical probability of a unit passing inspection: \[ \text{Probability of passing} = \frac{\text{Units that passed}}{\text{Total units inspected}} = \frac{850}{1000} = 0.85 \]

To convert this probability to a percentage, we multiply by 100: \[ 0.85 \times 100 = 85% \]

Now, if we consider the proportion of units that were rejected: \[ \text{Probability of rejection} = \frac{150}{1000} = 0.15 \]

Again, to convert this to a percentage: \[ 0.15 \times 100 = 15% \] Thus, the probability of passing inspection is \(1 - 0.15 = 0.85\) or \(85%\).

Now, we can look at the options provided: A) 0.15%
B) 3/20
C) 17/20
D) 1.5%

The closest correct option representing the probability of passing inspection as a fraction is C) 17/20, since: \[ \frac{17}{20} = 0.85 \text{ or } 85% \]

So the correct answer is C) 17/20.