Question

Use the following chemical equation to fill in the mole ratios for the reaction.

2N2 + 3O2 --> 2N2O3

mol N2 to mol O2

mol O2 to mol N2O3

mol N2 to mol N2O3

Answer 1

Based on the chemical equation you provided:

\[ 2N_2 + 3O_2 \rightarrow 2N_2O_3 \]

we can determine the mole ratios as follows:

1. **Mol N2 to Mol O2**: From the equation, 2 moles of \( N_2 \) react with 3 moles of \( O_2 \). Thus, the mole ratio of \( N_2 \) to \( O_2 \) is:
\[
\frac{2 \, \text{mol} \, N_2}{3 \, \text{mol} \, O_2}
\]

2. **Mol O2 to Mol N2O3**: From the equation, 3 moles of \( O_2 \) produce 2 moles of \( N_2O_3 \). Thus, the mole ratio of \( O_2 \) to \( N_2O_3 \) is:
\[
\frac{3 \, \text{mol} \, O_2}{2 \, \text{mol} \, N_2O_3}
\]

3. **Mol N2 to Mol N2O3**: From the equation, 2 moles of \( N_2 \) produce 2 moles of \( N_2O_3 \). Thus, the mole ratio of \( N_2 \) to \( N_2O_3 \) is:
\[
\frac{2 \, \text{mol} \, N_2}{2 \, \text{mol} \, N_2O_3} = 1
\]

Summarizing the mole ratios:

- **Mol N2 to Mol O2**: \( \frac{2}{3} \)
- **Mol O2 to Mol N2O3**: \( \frac{3}{2} \)
- **Mol N2 to Mol N2O3**: \( 1 \) (or \( \frac{1}{1} \))