Question

How many moles of NO2 are produced when 2.35 moles of N2O4 are decomposed according to the equation: N2O4 --> 2NO2?
Responses

4.7 mol
4.7 mol

2.35 mol
2.35 mol

1.125 mol
1.125 mol

0.5 mol

Answer 1

To determine how many moles of \( \text{NO}_2 \) are produced when 2.35 moles of \( \text{N}_2\text{O}_4 \) are decomposed according to the equation:

\[
\text{N}_2\text{O}_4 \rightarrow 2\text{NO}_2
\]

We see that 1 mole of \( \text{N}_2\text{O}_4 \) produces 2 moles of \( \text{NO}_2 \). Therefore, if you start with 2.35 moles of \( \text{N}_2\text{O}_4 \), the amount of \( \text{NO}_2 \) produced will be:

\[
2.35 \, \text{moles of } \text{N}_2\text{O}_4 \times \frac{2 \, \text{moles of } \text{NO}_2}{1 \, \text{mole of } \text{N}_2\text{O}_4} = 4.7 \, \text{moles of } \text{NO}_2
\]

Thus, 4.7 moles of \( \text{NO}_2 \) are produced.

So the correct answer is:

**4.7 mol**