Let's analyze the problem using the standard deck of cards.
Question 1
Event A: Choosing an ace. In a standard deck, there are 4 aces (one for each suit: hearts, diamonds, clubs, spades).
Event B: Choosing a red card. There are 26 red cards in a standard deck (13 diamonds and 13 hearts).
1. P(A ∩ B): This is the probability of choosing a card that is both an ace and a red card. The only red aces are the Ace of Diamonds and the Ace of Hearts, so there are 2 cards that satisfy both criteria.
\[ P(A \cap B) = \frac{\text{Number of favorable outcomes for } A \cap B}{\text{Total number of outcomes}} = \frac{2}{52} = \frac{1}{26} \]
2. P(A): The probability of choosing an ace.
\[ P(A) = \frac{\text{Number of aces}}{\text{Total number of cards}} = \frac{4}{52} = \frac{1}{13} \]
3. P(B): The probability of choosing a red card.
\[ P(B) = \frac{\text{Number of red cards}}{\text{Total number of cards}} = \frac{26}{52} = \frac{1}{2} \]
Summary for Question 1:
- \( P(A \cap B) = \frac{1}{26} \)
- \( P(A) = \frac{1}{13} \)
- \( P(B) = \frac{1}{2} \)
Question 2
Are events A and B dependent?
Events A and B are dependent if the occurrence of one affects the probability of the other occurring.
- If you pick a card and it's an ace (event A), it would change the composition of the deck, specifically affecting the probability of drawing a red card (event B).
- The probability of drawing a red card does change if you draw an ace (if you drew the Ace of Hearts or Ace of Diamonds, it would decrease the number of red cards).
Thus, the response is True.
Summary for Question 2:
- True: In the given situation, events A and B are dependent.