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Use the table to answer the question. Arrival Time Transport Type On Time Late TOTAL Car 164 48 212 Bus 46 62 108 TOTAL 210 110 320 Let event A represent an on-time arrival and event B represent transportation by bus. What is P(A and B) ? Round your answer to the nearest hundredth. (1 point) Responses 0.34 0.34 0.43 0.43 0.22 0.22 0.14

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To find \( P(A \text{ and } B) \), we need to determine the probability of an event where a passenger arrives on time (event A) and uses a bus (event B).

From the table, we have the following relevant values:

  • The number of passengers who arrived on time using a bus = 46
  • The total number of passengers = 320

The probability \( P(A \text{ and } B) \) is calculated as follows:

\[ P(A \text{ and } B) = \frac{\text{Number of on-time arrivals by bus}}{\text{Total number of passengers}} = \frac{46}{320} \]

Now, calculating the fraction:

\[ \frac{46}{320} = 0.14375 \]

Rounding it to the nearest hundredth, we get:

\[ 0.14 \]

So the answer is \( \boxed{0.14} \).