Question

Two more Algebra questions : Having some difficulty with these.

Drawing a blank on this one, not sure where to start.
Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x + 3y = 12 and passing through (9, -5).



I have half a solution to this one:
Solve the system of equations using the substitution method.
If the answer is a unique solution, present it as an ordered pair: (x, y). If not, specify whether the answer is “no solution” or “infinitely many solutions.”
4x + y = 4
2x + 8y = 0

First I did
4x - 4x + y = 4 - 4x
y = 4 - 4x
then
2x + 8(4-4x) = 0
2x + 32 - 32x = 0
2x + 32 - 32x = 0-32
2x - 32x = -32
-30x = -32
-30x/30 = -32/30
x = 32/30
x = 16/15

then
y = 4 - 4x
y = 4 - 4(16/15)
This is where I am stuck...


So i got x = 16/15 an y = ?

Answer 1

(I did not check you "x" if it is correct or not)

First, you need to simplify 4{16/15)
Then, find a common denominator

New Equation:
y = 60/15 - 64/15

Answer:
y = 4/15