Use the image to answer the question.

Question

A circular dial is divided into 10 equal parts from the origin toward the circumference. The parts are labeled clockwise from 1 to 28 in increments of 3. Beginning directly to the right, they are marked as 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28. A needle is fixed vertically at the center, with the arrow pointing directly upward to the line between 22 and 25 at the top center of the dial.

If this spinner is to be spun once, how likely will it stop on a multiple of 9?

(1 point)
Responses

impossible
impossible

likely
likely

certain
certain

unlikely

Answer 1

To determine the likelihood that the spinner will stop on a multiple of 9, we first need to identify the numbers present on the dial: 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28.

Next, we identify the multiples of 9 among those numbers. The multiples of 9 are:

• 9 (not on the dial)
• 18 (not on the dial)
• 27 (not on the dial)

Since there are no multiples of 9 listed on the dial, the spinner cannot land on a multiple of 9.

Therefore, the likelihood of the spinner stopping on a multiple of 9 is:

impossible.