Two people push on a 4 kg object. One force is 60N, north. The second force is 40N, east. Find the acceleration of the object. Ignore friction. The answer is 18m/s/s at 53.31 degrees.......but i don't know how to get to it.

Answer 1

Add the two forces to get the resultant force. Since they are at right angles,
the magnitude |F| is sqrt[60^2 + 40^2] = 72.11 N
The accleration is F/m = 18.02 m/s^2

The direction of the accleration is the direction of the resultant force, which you should be able to get from the ratio of the two forces (which is an arctangent of the angle from one axis)