Let \( r \) represent the number of red markers and \( b \) represent the number of blue markers.
Constraint 1: \( r + b = 16 \) (Total number of markers)
Constraint 2: \( b = 3r \) (Three times as many blue markers as red markers)
Now we can evaluate the scenarios:
-
For 3 red markers and 9 blue markers:
- \( r = 3 \)
- \( b = 9 \)
Checking the constraints:
- Constraint 1: \( 3 + 9 = 12 \) (Not met)
- Constraint 2: \( 9 = 3 \times 3 \) (Met)
Therefore, only Constraint 2 would be met.
-
For 6 red markers and 10 blue markers:
- \( r = 6 \)
- \( b = 10 \)
Checking the constraints:
- Constraint 1: \( 6 + 10 = 16 \) (Met)
- Constraint 2: \( 10 = 3 \times 6 \) (Not met)
Therefore, only Constraint 1 would be met.
Final answers:
- Only constraint 2 would be met if Ms. Rodriguez purchased 3 red markers and 9 blue markers.
- Only constraint 1 would be met if Ms. Rodriguez purchased 6 red markers and 10 blue markers.