Question

In which situation did the car achieve the greatest efficiency? (Assume the cars all have the same mass.)

a car that traveled 70 kilometers on 5.0 liters of gas
a car that traveled 70 kilometers on 5.0 liters of gas

a car that traveled 50 kilometers on 4.0 liters of gas
a car that traveled 50 kilometers on 4.0 liters of gas

a car that traveled 90 kilometers on 6.0 liters of gas
a car that traveled 90 kilometers on 6.0 liters of gas

a car that traveled 80 kilometers on 5.0 liters of gas

Answer 1

To determine which car achieved the greatest efficiency, we need to calculate the fuel efficiency (in kilometers per liter) for each of the given situations. The formula for fuel efficiency is:

\[
\text{Efficiency} = \frac{\text{Distance traveled (km)}}{\text{Liters of gas consumed (L)}}
\]

Let's calculate the efficiency for each situation:

1. **Car that traveled 70 kilometers on 5.0 liters of gas:**
\[
\text{Efficiency} = \frac{70 \text{ km}}{5.0 \text{ L}} = 14 \text{ km/L}
\]

2. **Car that traveled 50 kilometers on 4.0 liters of gas:**
\[
\text{Efficiency} = \frac{50 \text{ km}}{4.0 \text{ L}} = 12.5 \text{ km/L}
\]

3. **Car that traveled 90 kilometers on 6.0 liters of gas:**
\[
\text{Efficiency} = \frac{90 \text{ km}}{6.0 \text{ L}} = 15 \text{ km/L}
\]

4. **Car that traveled 80 kilometers on 5.0 liters of gas:**
\[
\text{Efficiency} = \frac{80 \text{ km}}{5.0 \text{ L}} = 16 \text{ km/L}
\]

Now, let's summarize the efficiencies for all cars:

- First car: 14 km/L
- Second car: 12.5 km/L
- Third car: 15 km/L
- Fourth car: 16 km/L

Based on this analysis, the car that traveled 80 kilometers on 5.0 liters of gas achieved the greatest efficiency of **16 km/L**.