Asked by Michelle
How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
Responses
none
none
more than one
more than one
one
Responses
none
none
more than one
more than one
one
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine how many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m, we can apply the Triangle Inequality Theorem. According to this theorem, for three lengths to form a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
Let's denote the sides as \( a = 5 \, m \), \( b = 5 \, m \), and \( c = 16 \, m \).
Now we check the inequalities:
1. \( a + b > c \):
\[
5 + 5 > 16 \rightarrow 10 > 16 \quad \text{(false)}
\]
2. \( a + c > b \):
\[
5 + 16 > 5 \rightarrow 21 > 5 \quad \text{(true)}
\]
3. \( b + c > a \):
\[
5 + 16 > 5 \rightarrow 21 > 5 \quad \text{(true)}
\]
Since the first inequality fails, the sides 5 m, 16 m, and 5 m cannot form a triangle.
Thus, the correct response is **none**.
Let's denote the sides as \( a = 5 \, m \), \( b = 5 \, m \), and \( c = 16 \, m \).
Now we check the inequalities:
1. \( a + b > c \):
\[
5 + 5 > 16 \rightarrow 10 > 16 \quad \text{(false)}
\]
2. \( a + c > b \):
\[
5 + 16 > 5 \rightarrow 21 > 5 \quad \text{(true)}
\]
3. \( b + c > a \):
\[
5 + 16 > 5 \rightarrow 21 > 5 \quad \text{(true)}
\]
Since the first inequality fails, the sides 5 m, 16 m, and 5 m cannot form a triangle.
Thus, the correct response is **none**.
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