Asked by brenda

T is in the interior of angle"PQR". if angle"PQR"=10X-7, angle"RQT"=5X and angle"PQT"=4x+6 "X" will eaqual to?
Answered by Henry
PQT + RQT = PQR,
(4X + 6) + 5X = 10X - 7,
4X + 5X - 10X = -7 - 6,
-X = -13,
X = 13.
Answered by Anonymous
why its 13 i didn't get it could u give me several steps
Answered by Anonymous
Par
Answered by Jake
My question is a bit different then this
Answered by Anonymous
It’s 123
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