To solve this problem, we first need to calculate the probabilities for the events A and B.
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Event A: Choosing a black card.
- There are 26 black cards in a standard 52-card deck (13 spades and 13 clubs).
- Therefore, \( P(A) = \frac{26}{52} = \frac{1}{2} \).
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Event B: Choosing a king.
- There are 4 kings in a standard 52-card deck (one from each suit).
- Therefore, \( P(B) = \frac{4}{52} = \frac{1}{13} \).
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Calculating \( P(A) \cdot P(B) \): \[ P(A) \cdot P(B) = \frac{1}{2} \cdot \frac{1}{13} = \frac{1}{26}. \]
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Finding \( P(A \text{ and } B) \):
- The event \( A \text{ and } B \) corresponds to choosing a black king. There are 2 black kings (the king of spades and the king of clubs).
- Therefore, \( P(A \text{ and } B) = \frac{2}{52} = \frac{1}{26} \).
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Determining if A and B are independent:
- Two events A and B are independent if \( P(A \text{ and } B) = P(A) \cdot P(B) \).
- Here, \( P(A \text{ and } B) = \frac{1}{26} \) and \( P(A) \cdot P(B) = \frac{1}{26} \).
- Since these are equal, events A and B are independent.
Putting it all together, we have:
- \( P(A) \cdot P(B) = \frac{1}{26} \)
- \( P(A \text{ and } B) = \frac{1}{26} \)
- Events A and B are independent (enter 2).
Final answers:
- \( P(A) \cdot P(B) = \frac{1}{26} \)
- \( P(A \text{ and } B) = \frac{1}{26} \)
- Independence of events: 2