Question
What is the volume of a shipping container that is 20 1/2 ft. long, 12 1/4 ft. wide, and 8 1/4 ft. tall? Apply the V=B×h formula to solve.(1 point)
251 1/8ft^3
41ft^3
169 1/8ft^3
2,071 25/32ft^3
251 1/8ft^3
41ft^3
169 1/8ft^3
2,071 25/32ft^3
Answers
GPT-4o mini
To find the volume of the shipping container using the formula \( V = B \times h \), where \( B \) is the base area and \( h \) is the height, we first need to calculate the base area.
1. **Calculate the base area \( B \)**:
- Length = 20 1/2 ft = \( 20.5 \) ft
- Width = 12 1/4 ft = \( 12.25 \) ft
Now multiply the length and width to find the area:
\[
B = \text{Length} \times \text{Width} = 20.5 \, \text{ft} \times 12.25 \, \text{ft}
\]
Performing the multiplication:
\[
B = 250.625 \, \text{ft}^2
\]
2. **Calculate the height \( h \)**:
- Height = 8 1/4 ft = \( 8.25 \) ft
3. **Calculate the volume \( V \)**:
\[
V = B \times h
\]
\[
V = 250.625 \, \text{ft}^2 \times 8.25 \, \text{ft}
\]
Now performing the multiplication:
\[
V = 250.625 \times 8.25 = 2,066.15625 \, \text{ft}^3
\]
To express this in a more usable form:
- The integer part is \( 2,066 \) ft³.
- The fractional part \( 0.15625 \) can be converted to an eighth denominator:
\[
0.15625 = \frac{15625}{100000} = \frac{1/16}
\]
Since \( \frac{15625}{100000} = 0.15625 \), the closest eighth we can consider is \( \frac{1}{8} \).
Thus the final volume is approximately:
\[
V \approx 2,066 1/8 \, \text{ft}^3
\]
In comparing options provided for answer choices, it appears \( 2,071 25/32\, \text{ft}^3 \) is the closest viable selection available, though it doesn't match the math derived here closely.
The most appropriate option considering our calculations is not listed directly, so it's best to restate the solution based on computations:
- The correct volume of the shipping container is approximately **2,066.15625 ft³**.
1. **Calculate the base area \( B \)**:
- Length = 20 1/2 ft = \( 20.5 \) ft
- Width = 12 1/4 ft = \( 12.25 \) ft
Now multiply the length and width to find the area:
\[
B = \text{Length} \times \text{Width} = 20.5 \, \text{ft} \times 12.25 \, \text{ft}
\]
Performing the multiplication:
\[
B = 250.625 \, \text{ft}^2
\]
2. **Calculate the height \( h \)**:
- Height = 8 1/4 ft = \( 8.25 \) ft
3. **Calculate the volume \( V \)**:
\[
V = B \times h
\]
\[
V = 250.625 \, \text{ft}^2 \times 8.25 \, \text{ft}
\]
Now performing the multiplication:
\[
V = 250.625 \times 8.25 = 2,066.15625 \, \text{ft}^3
\]
To express this in a more usable form:
- The integer part is \( 2,066 \) ft³.
- The fractional part \( 0.15625 \) can be converted to an eighth denominator:
\[
0.15625 = \frac{15625}{100000} = \frac{1/16}
\]
Since \( \frac{15625}{100000} = 0.15625 \), the closest eighth we can consider is \( \frac{1}{8} \).
Thus the final volume is approximately:
\[
V \approx 2,066 1/8 \, \text{ft}^3
\]
In comparing options provided for answer choices, it appears \( 2,071 25/32\, \text{ft}^3 \) is the closest viable selection available, though it doesn't match the math derived here closely.
The most appropriate option considering our calculations is not listed directly, so it's best to restate the solution based on computations:
- The correct volume of the shipping container is approximately **2,066.15625 ft³**.