Question

A bar of soap is 12 cm tall, 6 cm wide, and 10 cm long. It has a mass of 415 grams. What is the density of the bar of soap?

Question 1 options:

1.45 g/cm³


8.17 g/cm³


0.58 g/cm³


4.65 g/cm³

Answer 1

To find the density of the bar of soap, you can use the formula for density:

\[
\text{Density} = \frac{\text{Mass}}{\text{Volume}}
\]

First, we need to calculate the volume of the bar of soap. The volume \(V\) of a rectangular prism (which the bar of soap is) is given by:

\[
V = \text{height} \times \text{width} \times \text{length}
\]

Substituting in the dimensions of the bar of soap:

\[
V = 12 \, \text{cm} \times 6 \, \text{cm} \times 10 \, \text{cm}
\]
\[
V = 720 \, \text{cm}^3
\]

Now, we can substitute the mass and volume into the density formula:

\[
\text{Density} = \frac{415 \, \text{grams}}{720 \, \text{cm}^3}
\]

Calculating the density gives:

\[
\text{Density} \approx 0.5778 \, \text{g/cm}^3
\]

Rounding this to two decimal places results in approximately 0.58 g/cm³.

Thus, the density of the bar of soap is:

**0.58 g/cm³**