Question

Calculate the average travel time for each distance, and then use the results to calculate.

A 6-column table with 3 rows in the second, third, and fifth columns and 1 row in the other columns. The first column labeled Number of Washers has entry 1 washer mass = 4.9 grams. The second column labeled Trial has entries trial number 1, trial number 2, trial number 3. The third and fourth columns labeled Time to travel 0.25 meters t subscript 1 (seconds) have entries in the third column 2.24, 2.21, 2.23 and average in the fourth column. The fifth and sixth columns labeled time to travel 0.5 meters t subscript 2 (seconds) have entries in the fifth column 3.16, 3.08, 3.15 and in the sixth column average.
The average time that it takes for the car to travel the first 0.25m is
s.

The average time to travel just between 0.25 m and 0.50 m is
s.

Given the time taken to travel the second 0.25 m section, the velocity would be
m/s.

Answers

GPT-4o mini
To calculate the average travel times and the velocity, we will first find the average time for each distance segment and then calculate the velocity.

### Step 1: Calculate the Average Time for Each Distance

#### Average Time to Travel 0.25 Meters
We have the times for three trials for traveling 0.25 meters:
- Trial 1: 2.24 seconds
- Trial 2: 2.21 seconds
- Trial 3: 2.23 seconds

To find the average:

\[
\text{Average Time (0.25 m)} = \frac{(2.24 + 2.21 + 2.23)}{3} = \frac{6.68}{3} \approx 2.2267 \text{ seconds}
\]

### Step 2: Calculate the Average Time for 0.50 Meters

We have the times for three trials for traveling 0.5 meters:
- Trial 1: 3.16 seconds
- Trial 2: 3.08 seconds
- Trial 3: 3.15 seconds

To find the average:

\[
\text{Average Time (0.50 m)} = \frac{(3.16 + 3.08 + 3.15)}{3} = \frac{9.39}{3} \approx 3.13 \text{ seconds}
\]

### Step 3: Calculate the Time for the Second 0.25 Meters

To find the time taken to travel the second 0.25 meters, we need to subtract the average time for the first 0.25 meters from the average time for the total 0.5 meters:

\[
\text{Time for second 0.25 m} = \text{Average Time (0.50 m)} - \text{Average Time (0.25 m)}
\]
\[
\text{Time for second 0.25 m} = 3.13 - 2.2267 \approx 0.9033 \text{ seconds}
\]

### Step 4: Calculate the Velocity

Velocity is calculated using the formula:

\[
\text{Velocity} = \frac{\text{Distance}}{\text{Time}}
\]

For the second 0.25 meters, the distance is 0.25 meters and we have found the time to be approximately 0.9033 seconds:

\[
\text{Velocity} = \frac{0.25 \text{ m}}{0.9033 \text{ s}} \approx 0.276 \text{ m/s}
\]

### Summary of Results:
- The average time that it takes for the car to travel the first **0.25m** is approximately **2.23 seconds**.
- The average time to travel just between **0.25 m and 0.50 m** is approximately **0.9033 seconds**.
- The velocity for the second **0.25 m section** is approximately **0.276 m/s**.