To determine which event is most likely to occur, let's analyze the situation:
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Bread: There are 7 options. Hera has chosen sesame seed baguette, so the probability that the counter person chooses the same bread is \( \frac{1}{7} \).
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Meat: There are 5 options. Hera has chosen turkey, so the probability that the counter person chooses turkey is \( \frac{1}{5} \).
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Cheese: There are 4 options. Hera chose Swiss cheese, so the probability that the counter person chooses Swiss cheese is \( \frac{1}{4} \).
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Topping: There are 10 options. Hera has chosen pickles, so the probability that the counter person chooses pickles is \( \frac{1}{10} \).
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Dressing/Sauce: There are 6 options. Hera hasn't specified what dressing has been chosen, and since the question does not state a specific preference for dressing, we can assume that it is irrelevant to the other four items for the given scenario.
Now, let's compare the probabilities of each event:
- Probability of correct bread = \( \frac{1}{7} \)
- Probability of correct meat = \( \frac{1}{5} \)
- Probability of correct cheese = \( \frac{1}{4} \)
- Probability of correct topping = \( \frac{1}{10} \)
Among these probabilities:
- \( \frac{1}{5} \) (correct meat) is the highest probability.
- \( \frac{1}{4} \) (correct cheese) is slightly lower.
- \( \frac{1}{7} \) (correct bread) is lower than both.
- \( \frac{1}{10} \) (correct topping) is the lowest.
Based on these calculations, the event that is most likely to occur is Hera getting the correct meat.