Asked by Anonymous
Suppose that the area of a square is forty-one times its perimeter. Find the length of a side of the square.
Answers
Answered by
Anonymous
41(x+x+x+x)=x^2
since the area of a square is forty-one times its perimeter, I multiply 41 on the perimeter side to set the perimeter equal to the area
solve for x. you'll get two answers. eliminate the one that is equal to zero since a measure of length cannot equal to zero!
since the area of a square is forty-one times its perimeter, I multiply 41 on the perimeter side to set the perimeter equal to the area
solve for x. you'll get two answers. eliminate the one that is equal to zero since a measure of length cannot equal to zero!
Answered by
Anonymous
thank you ! I solved it
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