To solve the equation \(4x + 2(x - 3) = 6x - 6\), we will first simplify the left side:
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Distribute \(2\) in \(2(x - 3)\): \[ 2(x - 3) = 2x - 6 \]
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Now substitute this back into the equation: \[ 4x + 2x - 6 = 6x - 6 \]
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Combine like terms on the left side: \[ 6x - 6 = 6x - 6 \]
At this point, both sides of the equation are identical. This means that the equation holds true for all values of \(x\). Therefore, \(x\) can be any real number.
Thus, the solution is: \[ \text{All real numbers} , (x \in \mathbb{R}) \]