Question

Using the following information, make a prediction as to which event is most likely to occur. A sandwich shop has 7 options for bread, 5 options for meat, 4 options for cheese, 10 options for toppings, and 6 options for dressing or sauce. Hera places an order for a sesame seed baguette with turkey, Swiss cheese, pickles, and mayonnaise. The person behind the counter randomly chooses one bread, 1 meat, 1 cheese, 1 topping, and 1 dressing.(1 point) Responses Hera gets the correct bread. Hera gets the correct bread. Hera gets the correct topping. Hera gets the correct topping. Hera gets the correct cheese. Hera gets the correct cheese. Hera gets the correct meat.

Answer 1

To determine which event is most likely to occur in Hera's order, we can analyze the total number of combinations available at the sandwich shop.

1. Bread Options: 7 choices
2. Meat Options: 5 choices
3. Cheese Options: 4 choices
4. Topping Options: 10 choices
5. Dressing/Sauce Options: 6 choices

When the person behind the counter makes a selection, they choose one option from each category.

Now let's figure out the likelihood of selecting the specific options that Hera ordered:

1. The chance of getting the correct bread (sesame seed baguette) is \( \frac{1}{7} \).
2. The chance of getting the correct meat (turkey) is \( \frac{1}{5} \).
3. The chance of getting the correct cheese (Swiss cheese) is \( \frac{1}{4} \).
4. The chance of getting the correct topping (pickles) is \( \frac{1}{10} \).
5. The chance of getting the correct dressing (mayonnaise) is \( \frac{1}{6} \).

Now, let's compare these probabilities:

• Bread: \( \frac{1}{7} \) ≈ 0.1429
• Meat: \( \frac{1}{5} \) = 0.2
• Cheese: \( \frac{1}{4} \) = 0.25
• Topping: \( \frac{1}{10} \) = 0.1
• Dressing: \( \frac{1}{6} \) ≈ 0.1667

From this analysis, the highest probability occurs with the cheese option (Swiss cheese) at 0.25 (or \( \frac{1}{4} \)).

Therefore, the prediction for which event is most likely to occur is:

Hera gets the correct cheese.