Use the table to answer the question.   Arrival Time Transport Type On Time Late TOTAL Car 164 48 212 Bus 46 62 108 TOTAL 210 110 320 Let event A  represent an on-time arrival and event B  represent transportation by bus. What is P(A and B) ? Round your answer to the nearest hundredth. (1 point) Responses 0.22 0.22 0.34 0.34 0.43 0.43 0.14

1 answer

To find \(P(A \text{ and } B)\), we need to determine the probability that an arrival is on time (event A) and that the transport type is a bus (event B).

From the table, we can identify the counts:

  • The total number of arrivals: 320
  • The number of on-time arrivals by bus: 46

Now, we can calculate \(P(A \text{ and } B)\):

\[ P(A \text{ and } B) = \frac{\text{Number of on-time arrivals by bus}}{\text{Total number of arrivals}} = \frac{46}{320} \]

Calculating:

\[ P(A \text{ and } B) = \frac{46}{320} = 0.14375 \]

Rounding to the nearest hundredth:

\[ P(A \text{ and } B) \approx 0.14 \]

Thus, the answer is \( \boxed{0.14} \).