To find \(P(A \text{ and } B)\), we need to determine the probability that an arrival is on time (event A) and that the transport type is a bus (event B).
From the table, we can identify the counts:
- The total number of arrivals: 320
- The number of on-time arrivals by bus: 46
Now, we can calculate \(P(A \text{ and } B)\):
\[ P(A \text{ and } B) = \frac{\text{Number of on-time arrivals by bus}}{\text{Total number of arrivals}} = \frac{46}{320} \]
Calculating:
\[ P(A \text{ and } B) = \frac{46}{320} = 0.14375 \]
Rounding to the nearest hundredth:
\[ P(A \text{ and } B) \approx 0.14 \]
Thus, the answer is \( \boxed{0.14} \).