Question
Which figure has a greater area
12 cm by18.2 cm
13.5 cm x 15 cm
12 cm by18.2 cm
13.5 cm x 15 cm
Answers
Answered by
GPT-4o mini
To find which figure has a greater area, we will calculate the area of each rectangle using the formula:
\[
\text{Area} = \text{length} \times \text{width}
\]
1. For the first rectangle (12 cm by 18.2 cm):
\[
\text{Area}_1 = 12 \, \text{cm} \times 18.2 \, \text{cm} = 218.4 \, \text{cm}^2
\]
2. For the second rectangle (13.5 cm by 15 cm):
\[
\text{Area}_2 = 13.5 \, \text{cm} \times 15 \, \text{cm} = 202.5 \, \text{cm}^2
\]
Now, we compare the areas:
- Area of the first rectangle: \( 218.4 \, \text{cm}^2 \)
- Area of the second rectangle: \( 202.5 \, \text{cm}^2 \)
Since \( 218.4 \, \text{cm}^2 > 202.5 \, \text{cm}^2 \), the figure with dimensions 12 cm by 18.2 cm has a greater area.
\[
\text{Area} = \text{length} \times \text{width}
\]
1. For the first rectangle (12 cm by 18.2 cm):
\[
\text{Area}_1 = 12 \, \text{cm} \times 18.2 \, \text{cm} = 218.4 \, \text{cm}^2
\]
2. For the second rectangle (13.5 cm by 15 cm):
\[
\text{Area}_2 = 13.5 \, \text{cm} \times 15 \, \text{cm} = 202.5 \, \text{cm}^2
\]
Now, we compare the areas:
- Area of the first rectangle: \( 218.4 \, \text{cm}^2 \)
- Area of the second rectangle: \( 202.5 \, \text{cm}^2 \)
Since \( 218.4 \, \text{cm}^2 > 202.5 \, \text{cm}^2 \), the figure with dimensions 12 cm by 18.2 cm has a greater area.
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