To find the probability of selecting a student who wants the option to keep studying online or is a boy, we can use the principle of inclusion-exclusion.
Let's denote:
- \( A \) as the event of selecting a student who wants the option to keep studying online.
- \( B \) as the event of selecting a boy.
From the table:
- The number of students who want the option to keep studying online: \( |A| = 13 \)
- The number of boys: \( |B| = 10 \)
- The number of students who are both boys and want the option: \( |A \cap B| = 3 \)
Using the formula for the probability of the union of two events:
\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]
We can express the probabilities in terms of the total number of students, which is 25:
\[ P(A) = \frac{13}{25}, \quad P(B) = \frac{10}{25}, \quad P(A \cap B) = \frac{3}{25} \]
Thus, the probability can be calculated as:
\[ P(A \cup B) = \frac{13}{25} + \frac{10}{25} - \frac{3}{25} \]
This corresponds to the mathematical sentence:
\[ \frac{13}{25} + \frac{10}{25} - \frac{3}{25} \]
So, the correct response is:
1325 + 1025 - 325